Wednesday, July 27, 2016

Elongation index of the aggregate



Elongation Index of Aggregate
[BS 812 – Part 105.2: 1990]

·         Preparation of Specimens:
1.       Take quantity material of aggregate (bulk sample) randomly from source.
2.       Reduce the Sample to test portions by Sample Divider or Quartering with minimum mass as shown in Table 1:
Nominal size of material (mm)
40
28
20
14
10
Minimum mass of test portion (kg)
15
5
2
1
0.5

3.        



Dry the test portion in oven at (105±5) oC until constant mass, and then record Mo in (g).
·         Testing:
-          Place the test portion into container.
-          Discard all aggregates retained on 50.0 mm test sieve and Passing 6.30 mm.
-          Pour the residue on top of coarsest sieve and shake it manually or by mechanical shaker for sufficient time to separate into size fractions as in table 2:
Nominal size of test sieve (mm)
100% passing
50.0
37.5
28.0
20.0
14.0
10.0
100% retained
37.5
28.0
20.0
14.0
10.0
6.30
Gaps between pins of gauge (mm)
78.7
59.0
43.2
30.6
21.6
14.7
Minimum mass of test portion (kg)
35
15
5
2
1
0.5

-           
-        








  Check the separation is complete by hand sieving.
-          Weigh the individual size-fractions retained on each sieve in (g).
-          Sum the masses of the fractions (M1) in (g).
-          Calculate the individual percentage retained and discard fraction of less than 5%.
-          Record the remaining mass by (M2) in (g).
-          Gauge each size-fraction by length gauge.
-          Combine all Elongated particles (not passing) and weigh (M3) in (g).
·         Calculation:
-          Calculate the corrected mass of elongated particle (M4) in (g) = (M1/M2) xM3.
-          Calculate the % elongated particle (M5) = (M4/M1) x100.
-          Calculate the value of Elongation Index = (M5xM1)/100.
-          Express Elongation Index to nearest whole number.

No comments:

Post a Comment